by ecstasy » September 27th, 2007, 8:12 pm
well, i know that if you plot the derivative of cos u get sin and vice versa... its hard to explain, but wenever the slope of the cos graph is zero, then it is an X intercept for the derivative, if you r using a ti 83+ graphing calculator, u can type into the graph screen
y1=cosx
y2=Nderive(y1,x,x)
(to get nderive, type "math" > "8")
and it will graph cos and its derivative function, sin
(to find y1, press "vars" > "yvars" > "y1"
but, im really not sure how to explain it in algebraic form but graphically yes, i actually just took a test where i had to graph the derivative function of it, like
f(x)=x^3 f'(x)=3x^2
where f' is its derivative function, so
f(x)=cosx f'(x)=? im not sure how to use the power rule on that :S
but i do know that wen the graph hits a high point or a low point and the slope is zero, then that is a intercept of the same y value on the x-axis, then u just connect the dots logically based on the slope of the curves.
i know this isnt much help but its all i can do :S
well, i know that if you plot the derivative of cos u get sin and vice versa... its hard to explain, but wenever the slope of the cos graph is zero, then it is an X intercept for the derivative, if you r using a ti 83+ graphing calculator, u can type into the graph screen
y1=cosx
y2=Nderive(y1,x,x)
(to get nderive, type "math" > "8")
and it will graph cos and its derivative function, sin
(to find y1, press "vars" > "yvars" > "y1"
but, im really not sure how to explain it in algebraic form but graphically yes, i actually just took a test where i had to graph the derivative function of it, like
f(x)=x^3 f'(x)=3x^2
where f' is its derivative function, so
f(x)=cosx f'(x)=? im not sure how to use the power rule on that :S
but i do know that wen the graph hits a high point or a low point and the slope is zero, then that is a intercept of the same y value on the x-axis, then u just connect the dots logically based on the slope of the curves.
i know this isnt much help but its all i can do :S